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- Thickness of brake pad (>6 mm) - current is less than 5mm, need to buy new ones. New ones have 0.3 inches thick
- Brake pad contact area (>600mm^2) - should be 2 inches area contact
- Maximum pressure allowed in brake lines - assume lines meet max pressure
Relevant Equations From Unknown Source
See Updated Formula below for a better description.
Possibly this site - http://www.engineeringinspiration.co.uk/brakecalcs.html
Braking Force
Wheel Lock
Brake Torque
Disc Effective Radius (Full Circle)
Clamp Load
System Pressure
See page for other calculations. I still need to double check that these apply to our car and can be properly used. Also, can use FBD to determine braking force for deceleration. Formulas for stopping distance also from above page.
Results
Weight of Car | Results | Rear Braking Required | Does our system work? |
---|---|---|---|
400kg | |||
500kg | |||
600kg | |||
700kg | |||
800kg | |||
900kg | |||
1000kg |
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Normal force on the front and rear of the car is
Nf = [(CGf)W + 20hCG(Fb)]/100WB
Nr = [(CGr)W - 20hCG(Fb)]/100WB
Nf = normal force on front of car
Nr = Normal force on rear of car
CGf = % along wheelbase center distance from centre of gravity is (example if front and rear wheels are 150cm away and cg is 90cm away from rear, CGf = 60)CGr = % along wheelbase center of gravity is (if 90 cm away from rear, CGr = 40)to rear wheel
CGr = distance from centre of gravity to front wheel
WB = length of the wheel base
hCG = height of the centre of gravity off the ground
Fb = mass of car multiplied by deceleration
W = car weight (kgN)
Torque of the brake when locking up occurs is given to be
T = (f)(N)r/2
f = coefficient of friction between tires and road
T = torque
r = tire radius (m)
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