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  1. Thickness of brake pad (>6 mm) - current is less than 5mm, need to buy new ones. New ones have  0.3 inches thick
  2. Brake pad contact area (>600mm^2) - should be 2 inches area contact
  3. Maximum pressure allowed in brake lines - assume lines meet max pressure


Relevant Equations From Unknown Source

See Updated Formula below for a better description. 

Possibly this site - http://www.engineeringinspiration.co.uk/brakecalcs.html

Braking Force

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Wheel Lock

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Brake Torque

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Disc Effective Radius (Full Circle)

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Clamp Load

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System Pressure

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See page for other calculations. I still need to double check that these apply to our car and can be properly used. Also, can use FBD to determine braking force for deceleration. Formulas for stopping distance also from above page.




Results

Weight of CarResultsRear Braking RequiredDoes our system work?
400kg


500kg


600kg


700kg


800kg


900kg


1000kg


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Normal force on the front and rear of the car is

Nf = [(CGf)W + 20hCG(Fb)]/100WB

Nr = [(CGr)W - 20hCG(Fb)]/100WB

Nf = normal force on front of car

Nr = Normal force on rear of car

CGf = % along wheelbase center distance from centre of gravity is (example if front and rear wheels are 150cm away and cg is 90cm away from rear, CGf = 60)CGr = % along wheelbase center of gravity is (if 90 cm away from rear, CGr = 40)to rear wheel

CGr = distance from centre of gravity to front wheel

WB = length of the wheel base

hCG = height of the centre of gravity off the ground

Fb = mass of car multiplied by deceleration

W = car weight (kgN)


Torque of the brake when locking up occurs is given to be 

T = (f)(N)r/2

f = coefficient of friction between tires and road

T = torque

r = tire radius (m)

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