For calculating loads at the bellcrank we can use the pushrod force and make some assumptions. We assume that:

We are using the worst pushrod loading case, which occurs in the front outside pushrod for the conditions above.
Forces balance out
All force is in the Y-Z plane
The coilover node is 1.75x as far as the pushrod node (overestimation, actually 1.72)
The bellcrank-chassis joint provides no moment about the X-axis
Full coilover compression occurs at 40mm from the coilover’s neutral 1g position
When the coilover is fully compressed its behaviour changes from a spring (resists force based on displacement) to a rod (resists all force)
The worst loading condition is when the coilover is fully compressed

*Note: in some scenarios, it is possible that the loading is worse when the net force vector points directly away from A. While the magnitude will be less, the force will be borne by the weakest part of the bellcrank. However, based on rough calculations the force is not significant until the coilover is fully compressed.

Given the angles and magnitudes above we can find the normal and tangential components of both forces relative to A, knowing that the bellcrank has no moment in the X about A when fully compressed.

Worst Case Loading (N)
Conditions	Ft Pushrod	Fn Pushrod	Ft Coilover	Fn Coilover
Braking & Cornering Outer (outside front wheel)	-9085	6127	5191	1489

We can translate these forces into our more convenient Y-Z axes.

Worst Case Loading (N)
Conditions	Fy Coilover	Fz Coilover	Fy Pushrod	Fz Pushrod
Braking & Cornering Outer (outside front wheel)	5360	658	9490	5479

To maintain static equilibrium, the forces at A must oppose all forces at B and C.

Worst Case Loading (N)
Conditions	Fy at chassis pin	Fz at chassis pin
Braking & Cornering Outer (outside front wheel)	-14850	-6137

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