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Normal force on the front and rear of the car is
Nf = [(CGf)W + 20hCG(Fb)]/100WB
Nr = [(CGr)W - 20hCG(Fb)]/100WB
Nf = normal force on front of car
Nr = Normal force on rear of car
CGf = % along wheelbase center distance from centre of gravity is (example if front and rear wheels are 150cm away and cg is 90cm away from rear, CGf = 60)CGr = % along wheelbase center of gravity is (if 90 cm away from rear, CGr = 40)to rear wheel
CGr = distance from centre of gravity to front wheel
WB = length of the wheel base
hCG = height of the centre of gravity off the ground
Fb = mass of car multiplied by deceleration
W = car weight (kgN)
Torque of the brake when locking up occurs is given to be
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